Question Number 163327 by mathlove last updated on 06/Jan/22 | ||
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$$\left(\mathrm{1}+\frac{\mathrm{20}}{\mathrm{100}}\right)^{{n}} =\frac{\mathrm{216}}{\mathrm{125}}\:\:\:\:\:\:{n}=? \\ $$ | ||
Answered by Rasheed.Sindhi last updated on 06/Jan/22 | ||
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$$\left(\mathrm{1}+\frac{\mathrm{20}}{\mathrm{100}}\right)^{{n}} =\frac{\mathrm{216}}{\mathrm{125}}\:\:\:\:\:\:{n}=? \\ $$$$\left(\frac{\mathrm{6}}{\mathrm{5}}\right)^{{n}} =\left(\frac{\mathrm{6}}{\mathrm{5}}\right)^{\mathrm{3}} \\ $$$${n}=\mathrm{3} \\ $$ | ||
Commented by peter frank last updated on 06/Jan/22 | ||
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$$\mathrm{great} \\ $$ | ||