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Question Number 36227 by Cheyboy last updated on 30/May/18

1×10^(7 ) electrons pass through a   conductor in 1.0μs.Find the   current in Amperes flowing  through the conductor.  electronic charge=1.6×10^(−19) C

$$\mathrm{1}×\mathrm{10}^{\mathrm{7}\:} {electrons}\:{pass}\:{through}\:{a}\: \\ $$$${conductor}\:{in}\:\mathrm{1}.\mathrm{0}\mu{s}.{Find}\:{the}\: \\ $$$${current}\:{in}\:{Amperes}\:{flowing} \\ $$$${through}\:{the}\:{conductor}. \\ $$$${electronic}\:{charge}=\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} {C} \\ $$

Answered by last updated on 30/May/18

i=((ne)/t)=((1×10^7 ×1.6×10^(−19) )/(1×10^(−6) )) amp

$${i}=\frac{{ne}}{{t}}=\frac{\mathrm{1}×\mathrm{10}^{\mathrm{7}} ×\mathrm{1}.\mathrm{6}×\mathrm{10}^{−\mathrm{19}} }{\mathrm{1}×\mathrm{10}^{−\mathrm{6}} }\:{amp} \\ $$

Commented by Cheyboy last updated on 30/May/18

Thank u sir

$${Thank}\:{u}\:{sir}\: \\ $$

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