Question Number 225691 by fantastic last updated on 07/Nov/25
$$\sqrt[{{i}}]{−\mathrm{1}} \\ $$
Answered by mehdee7396 last updated on 07/Nov/25
$$\left({e}^{{i}\pi} \right)^{\frac{\mathrm{1}}{{i}}} ={e}^{\pi} \\ $$
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Question Number 225691 by fantastic last updated on 07/Nov/25 | ||
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$$\sqrt[{{i}}]{−\mathrm{1}} \\ $$ | ||
Answered by mehdee7396 last updated on 07/Nov/25 | ||
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$$\left({e}^{{i}\pi} \right)^{\frac{\mathrm{1}}{{i}}} ={e}^{\pi} \\ $$ | ||