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Question Number 131083 by Dwaipayan Shikari last updated on 01/Feb/21

1−(1/(5−((16)/(13−((81)/(25−((256)/(41−((625)/(61−((1296)/(85−((2401)/(113−...))))))))))))))=(6/𝛑^2 )

$$\mathrm{1}−\frac{\mathrm{1}}{\mathrm{5}−\frac{\mathrm{16}}{\mathrm{13}−\frac{\mathrm{81}}{\mathrm{25}−\frac{\mathrm{256}}{\mathrm{41}−\frac{\mathrm{625}}{\mathrm{61}−\frac{\mathrm{1296}}{\mathrm{85}−\frac{\mathrm{2401}}{\mathrm{113}−...}}}}}}}=\frac{\mathrm{6}}{\boldsymbol{\pi}^{\mathrm{2}} } \\ $$

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