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Question Number 6979 by Fitrah A last updated on 04/Aug/16

$$\underset{0}{\stackrel{\pi }{\int }}(sin3x+cosx)dx=?$$

Answered by sandy_suhendra last updated on 04/Aug/16

$$={[-\frac{1}{3}cos3x+sinx]}_0^{\pi }$$$$=(-\frac{1}{3}cos3\pi +sin\pi )-(-\frac{1}{3}cos0+sin0)$$$$=(\frac{1}{3}+0)-(-\frac{1}{3}+0)$$$$=\frac{2}{3}$$

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