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Question Number 136481 by BHOOPENDRA last updated on 22/Mar/21

∫_0 ^((50π)/3) ∣sinx∣dx

$$\int_{\mathrm{0}} ^{\frac{\mathrm{50}\pi}{\mathrm{3}}} \mid{sinx}\mid{dx} \\ $$

Answered by MJS_new last updated on 22/Mar/21

∫_0 ^(50π/3) ∣sin x∣dx=33∫_0 ^(π/2) sin x dx+∫_(π/2) ^(2π/3) sin x dx=((67)/2)

$$\underset{\mathrm{0}} {\overset{\mathrm{50}\pi/\mathrm{3}} {\int}}\mid\mathrm{sin}\:{x}\mid{dx}=\mathrm{33}\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\mathrm{sin}\:{x}\:{dx}+\underset{\pi/\mathrm{2}} {\overset{\mathrm{2}\pi/\mathrm{3}} {\int}}\mathrm{sin}\:{x}\:{dx}=\frac{\mathrm{67}}{\mathrm{2}} \\ $$

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