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Question Number 218063 Answers: 0 Comments: 0
$$\int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\mathrm{cos}\:{x}^{\mathrm{2}} \\ $$
Question Number 218057 Answers: 1 Comments: 0
$${Solve} \\ $$$$\left({x}−\mathrm{3}\right)^{\mathrm{5}/\mathrm{3}} −\mathrm{6}\left({x}−\mathrm{3}\right)^{\mathrm{2}/\mathrm{3}} −\mathrm{8}=\mathrm{0} \\ $$
Question Number 218055 Answers: 1 Comments: 1
Question Number 218054 Answers: 0 Comments: 0
Question Number 218047 Answers: 3 Comments: 0
$${Determine}\:{x}: \\ $$$$\sqrt{{x}+\mathrm{3}}\:+\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{1}}\:=\mathrm{2} \\ $$
Question Number 218046 Answers: 0 Comments: 0
Question Number 218045 Answers: 0 Comments: 0
Question Number 218041 Answers: 1 Comments: 0
$${find}\:\left({x},{y},{z}\right)/{such}\:{as} \\ $$$$\left({x}+{y}+{z}=\mathrm{1}\right. \\ $$$$\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{z}^{\mathrm{2}} \:=\mathrm{9}\right. \\ $$$$\left(\frac{\mathrm{1}}{{x}}+\frac{\mathrm{1}}{{y}}+\frac{\mathrm{1}}{{z}}=\mathrm{1}\right. \\ $$
Question Number 218036 Answers: 2 Comments: 0
$${Solve} \\ $$$$\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} \:+\:\mathrm{xy}\:=\:\mathrm{19}\: \\ $$$$\:\mathrm{x}\:+\:\mathrm{y}=\:\mathrm{5} \\ $$
Question Number 218030 Answers: 0 Comments: 6
Question Number 218025 Answers: 0 Comments: 0
$$ \\ $$$$\:\:\:\mathrm{I}=\int_{\mathrm{0}} ^{\:\infty} {te}^{−{t}} {J}_{−\frac{\mathrm{1}}{\mathrm{2}}} \:\left({t}\:\right)\:{dt}\:=? \\ $$$$ \\ $$
Question Number 218021 Answers: 1 Comments: 0
Question Number 218019 Answers: 2 Comments: 0
$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{x}+{y}=\mathrm{18} \\ $$$${xy}+{x}+{y}=\mathrm{7} \\ $$$${Solve}. \\ $$
Question Number 218013 Answers: 1 Comments: 0
Question Number 218005 Answers: 0 Comments: 2
$$\: \\ $$$$\: \\ $$$$\:\boldsymbol{\mathrm{if}}\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\boldsymbol{\mathrm{y}}^{\mathrm{2}} +\boldsymbol{\mathrm{z}}^{\mathrm{2}} =\mathrm{1},\: \\ $$$$\:\boldsymbol{\mathrm{maximum}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{x}}\mathrm{y}+\mathrm{2yz}\:=\:... \\ $$
Question Number 218003 Answers: 0 Comments: 6
$$\mathrm{1}.\:\:\:\int\:\:\frac{\mathrm{x}\:\mathrm{dx}}{\left(\mathrm{x}\:+\:\mathrm{2}\right)\centerdot\left(\mathrm{x}\:+\:\mathrm{4}\right)} \\ $$$$\mathrm{2}.\:\:\:\int\:\:\frac{\mathrm{x}\:+\:\mathrm{2}}{\mathrm{x}^{\mathrm{3}} \:−\:\mathrm{2x}^{\mathrm{2}} }\:\mathrm{dx} \\ $$$$\mathrm{3}.\:\:\:\int\:\:\frac{\mathrm{2x}\:+\:\mathrm{7}}{\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{4x}\:+\:\mathrm{3}}\:\mathrm{dx} \\ $$
Question Number 217992 Answers: 0 Comments: 0
Question Number 217991 Answers: 1 Comments: 0
$${x}^{\mathrm{2}} +\mathrm{3}=\mathrm{0} \\ $$$${x}^{\mathrm{2}} +\mathrm{5}=\mathrm{3} \\ $$
Question Number 217985 Answers: 1 Comments: 3
$$\mathrm{x}^{\mathrm{3}} \:−\:\mathrm{3x}\:+\:\mathrm{1}\:=\:\mathrm{0} \\ $$$$\mathrm{The}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{the}\:\mathrm{equation}\:\rightarrow\:\mathrm{a}\:,\:\mathrm{b}\:,\:\mathrm{c} \\ $$$$\mathrm{Find}\:\rightarrow\:\sqrt[{\mathrm{3}}]{\mathrm{a}}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{b}}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{c}}\:=\:? \\ $$
Question Number 217982 Answers: 0 Comments: 2
$${Solve} \\ $$$${If}\:\mathrm{4}^{\mathrm{2}^{\mathrm{2}{y}−\mathrm{1}\:} } =\:\mathrm{16}^{\mathrm{4}^{{y}+\mathrm{1}} } \:{and}\:\mathrm{8}^{\mathrm{3}^{\mathrm{2}{x}−\mathrm{1}} } =\:\mathrm{2}^{\mathrm{9}^{\mathrm{2}−{x}} } \\ $$$${what}\:{is}\:\mathrm{2}{x}\:+\:{y}? \\ $$
Question Number 217964 Answers: 0 Comments: 0
Question Number 217958 Answers: 2 Comments: 2
$${a},{b},{c}\in\mathbb{Z}^{+} {and} \\ $$$${a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +{ab}+{bc}+{ca}=\mathrm{2025} \\ $$$${find}\:{out}\:{all}\:{triplets}\:\left({a},{b},{c}\right). \\ $$
Question Number 217952 Answers: 2 Comments: 0
$${If}\:{x}\in\mathbb{Z}\:\wedge{y}\:{non}-{negative}\:{integer} \\ $$$${such}\:{that} \\ $$$${x}^{\mathrm{2}} +\mathrm{10}{x}+\mathrm{23}=\mathrm{2}^{{y}} \\ $$$${find}\:{out}\:{x},{y} \\ $$
Question Number 217949 Answers: 1 Comments: 1
Question Number 217940 Answers: 3 Comments: 0
$${Solve} \\ $$$$\sqrt{\mathrm{2}{x}+\mathrm{7}}\:\:−\sqrt{{x}−\mathrm{1}}\:=\mathrm{2}\:\:\:\:\:\:\:\:\:\:\: \\ $$
Question Number 217937 Answers: 0 Comments: 5
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