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Question Number 220366 Answers: 1 Comments: 0
$$\boldsymbol{\mathrm{solve}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{system}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{equation}} \\ $$$$\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{gaussian}}\:\boldsymbol{\mathrm{elimination}}\:\boldsymbol{\mathrm{method}} \\ $$$$\boldsymbol{\mathrm{x}}+\mathrm{2}\boldsymbol{\mathrm{y}}+\mathrm{3}\boldsymbol{\mathrm{z}}=\mathrm{10} \\ $$$$\mathrm{2}\boldsymbol{\mathrm{x}}−\mathrm{3}\boldsymbol{\mathrm{y}}+\boldsymbol{\mathrm{z}}=\mathrm{1} \\ $$$$\mathrm{3}\boldsymbol{\mathrm{x}}+\boldsymbol{\mathrm{y}}−\mathrm{2}\boldsymbol{\mathrm{z}}=\mathrm{9} \\ $$
Question Number 220365 Answers: 3 Comments: 0
Question Number 220362 Answers: 0 Comments: 0
Question Number 220361 Answers: 0 Comments: 0
Question Number 220340 Answers: 2 Comments: 0
Question Number 220320 Answers: 1 Comments: 3
Question Number 220353 Answers: 1 Comments: 3
Question Number 220307 Answers: 1 Comments: 0
Question Number 220286 Answers: 3 Comments: 5
Question Number 220278 Answers: 0 Comments: 0
Question Number 220269 Answers: 1 Comments: 0
$$\underset{{t}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\:\frac{{C}_{\mathrm{1}} {J}_{\nu} \left({t}\right)+{C}_{\mathrm{2}} {Y}_{\nu} \left({t}\right)+\boldsymbol{\mathrm{H}}_{\nu} \left({t}\right)}{{C}_{\mathrm{1}} {J}_{\nu} \left({t}\right)+{C}_{\mathrm{2}} {Y}_{\nu} \left({t}\right)}=?? \\ $$$$\nu\in\mathbb{R} \\ $$$${J}_{\nu} \left({z}\right)\:\mathrm{Bessel}\:\mathrm{function}\:\mathrm{First}\:\mathrm{kind} \\ $$$${Y}_{\nu} \left({z}\right)\:\mathrm{Bessel}\:\mathrm{function}\:\mathrm{Second}\:\mathrm{Kind} \\ $$$$\boldsymbol{\mathrm{H}}_{\nu} \left({z}\right)\:\mathrm{Struve}\:\mathrm{H}\:\mathrm{function} \\ $$
Question Number 220266 Answers: 1 Comments: 0
$$\mathrm{2}^{\mathrm{a}} \:\:+\:\:\mathrm{2}^{\mathrm{b}} \:\:+\:\:\mathrm{2}^{\mathrm{c}} \:\:=\:\:\mathrm{148} \\ $$
Question Number 220264 Answers: 1 Comments: 0
Question Number 220263 Answers: 3 Comments: 0
Question Number 220262 Answers: 4 Comments: 0
Question Number 220257 Answers: 2 Comments: 0
$${proof}\:{that}\:{volume}\:{of}\:{frustum}\:{of} \\ $$$$\:{circular}\:{cone}\:{is}\:\frac{\mathrm{1}}{\mathrm{3}}{h}\left[{A}\mathrm{1}+{A}\mathrm{2}+\sqrt{{A}\mathrm{1}{A}\mathrm{2}}\right. \\ $$$${A}_{\mathrm{1}} {and}\:{A}_{\mathrm{2}} \:{are}\:\:{areas}\:{of}\:{base} \\ $$
Question Number 220253 Answers: 0 Comments: 0
Question Number 220250 Answers: 1 Comments: 0
Question Number 220249 Answers: 0 Comments: 0
Question Number 220248 Answers: 0 Comments: 0
Question Number 220247 Answers: 1 Comments: 0
Question Number 220246 Answers: 6 Comments: 0
Question Number 220245 Answers: 0 Comments: 0
Question Number 220244 Answers: 0 Comments: 0
Question Number 220243 Answers: 5 Comments: 0
Question Number 220242 Answers: 0 Comments: 0
$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int\:\:\frac{{ln}\:{x}}{\left(\mathrm{1}\:+\:{x}^{\mathrm{2}} \right)\:^{\mathrm{2}} }\:\:{dx} \\ $$$$ \\ $$
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